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Given a string in Java, how can I obtain a new string where all adjacent sequences of digits are reversed?

My code:

import static java.lang.System.*;public class P2{    public static void main(String[] args)    {        if(args.length < 1)        {            err.printf("Usage: java -ea P2 String [...]\n");            exit(1);        }        String[] norm = new String[args.length];        for(int i = 0; i<norm.length;i++)        {            norm[i] = args[i];        }    }    public String invertDigits(String[] norm)    {       }}

And as an example, this is what it should do:

Inputs: 1234 abc9876cba a123 312asd a12b34c56d

1234 -> 4321

abc9876cba -> abc6789cba

a123 -> a321

312asd -> 213asd

a12b34c56d -> a21b43c65d

I have the following dataframe.

    ID  LOC Alice   Bob  Karen0   1   CH  9|5 6|3 4|41   2   ES  1|1 0|8 2|02   3   DE  2|4 6|6 3|13   4   ES  3|9 1|2 4|2

Alice and Bob columns contain string values. I want to reverse the strings in these columns conditional on the value of another column. For example, where LOC==ES, reversing the strings in the corresponding columns would look like:

    ID  LOC Alice   Bob   Karen0   1   CH  9|5 6|3 4|41   2   ES  1|1 8|0 0|22   3   DE  2|4 6|6 3|13   4   ES  9|3 2|1 2|4

Is there a fast way to perform this operation on all matching rows in a csv file with thousands rows?

Thank you.

Problem Statement: Write a function of the declaration void str_words_in_rev(char *input, int length) that reverses the words in a string of word/(s). I've implemented two different solutions for it, one of which is extremely complicated.

Solution 1: I reverse the entire string using void reverse(char* string, int start, int end) function which takes the index of the first and last letter of the string or substring you want to reverse. After that, I reverse each word in the string using the same reverse function.

#include<stdio.h>void swapChar(char *a, char *b) {  char temp = *a;  *a = *b;  *b = temp;}int length(char *string) {  if(string == NULL)     return -1;  int i=0;  for(;string[i++];);  return i;}void reverse(char* string, int start, int end) {  int mid = start + (end - start + 1)/2;  for(int i=start,j=end;i<mid;)    swapChar(&string[i++], &string[j--]);}int main() {  char str[] = "abc def ghij klmn";  int i=0, j=0, len = length(str), flag = 0;  if(str == NULL || !(*str))     return 0;  for(;str[j]!='\0';++j) {     if(str[j] == ' ') {       flag = 1;       reverse(str,i,j-1);       i = j+1;     }  }  if(flag == 1) {  reverse(str, i, j-1);  reverse(str,0,len-2);  }  printf("%s\n", str);  return 0;}

Solution 2: I shift every word and following space character (after rearranging it) towards the end by using the pushToEnd function and then shift the end before the end word which was pushed. There are printf statements which can be commented out to really understand what's happening, if my explanation is inadequate (which I apologise for).

        int pushToEnd(char *str, int length) {        int len = 0;        int i = 0, j = 0, k = 0, n = 0;        for (i = 0; str[i++] != ' ' && i <= length;)            ++len;        if (len == length)            return len;        //printf("Length of first word:");        //printf("%d\n", len);        for (j = i - 1; j>0; --j)            swapChar(&str[j], &str[j - 1]);        ++len;        //printf("After rearranging first word:");        //printf("%s\n", str);        //printf("Pushing first word toward the end\n");        for (; k + 2 * len <= length; k = k + len) {            for (int l = k; l<k + len; ++l) {                swapChar(&str[l], &str[l + len]);            }            //printf("---%s---\n", str);        }        //printf("As blocks:");        //printf("%s\n", str);        //printf("K VALUE: %d\n", k);        for (; k + len<length; ++k) {            for (n = k + len; n>k; --n) {                //printf("N VALUE: %d\n", n);                swapChar(&str[n], &str[n - 1]);            }        }        //printf("One by one:");        //printf("%s\n", str);        return len;    }    void str_words_in_rev1(char *input, int length){    int len = 0;    for (int end = length; end>0; end = end - len) {        //printf("End:%d\n", end);        len = pushToEnd(input, end);    }}

Once you've understood the problem statement and the solutions I've implemented, here are my questions:

what is the time complexity of my solutions? I think the first solution has O(n) complexity and the second one is probably O(n^2) but I'm not sure.

Neither solutions account for asymmetrical spacing. The words are reversed and spacing is reversed as well. It's imperceptible in cases where there is symmetrical spacing/multi-symmetrical spacing. The problem statement was unclear on this, but I'd like your views on whether it should be accounted for.

So I'm brand new to Java and am taking a Udemy course. I'm at the point where I've been given an assignment to printing a string in reverse. I can achieve this, but not without printing each character individually. My code and response below should clarify:

   /*ReverseString     * */    import java.util.Scanner;    public class reversestring {        public static void main(String[]args) {        String inStr;//input string        String reverse = "";        int inStrLen; //length of the input String        Scanner in = new Scanner(System.in);        System.out.print("Enter a String: ");        inStr = in.next(); //use next() to read a string        inStrLen = inStr.length();        //use inStr.charAt(index) in a loop to extract character at "index" from inStr        // The string's index begins at 0 from the left.         for (int i = inStrLen - 1; i >= 0; --i) { //Process the String from the right            reverse = reverse + inStr.charAt(i);            System.out.print("The reverse of string "+ inStr + " is " + reverse);        }    }    }

Response:

Enter a String: 234The reverse of string 234 is 4The reverse of string 234 is 43The reverse of string 234 is 432

I would just like the code to ouput "The reverse of string 234 is 432". I'm sure I'm making this harder than it really is. Any advice would be helpful.

Thanks!

I'm trying to reverse a string and add spaces from 3 in 3 characters the code I have right now is this:

$rowPreco = "925000"   $rowPreco = strrev($rowPreco);$rowPreco = wordwrap($rowPreco , 3 , ' ' , true );$rowPreco = strrev($rowPreco);

if I take the strrev out it prints how I want ("925 000") but if I have the strrev it will print ("92 500 0").

But I need to use the strrev because if the value is ("1200000") it will print ("120 000 0") instead of ("1 200 000").

Any help would be appreciated.

Thanks!

UPDATE!

When I use the number_format it will ignore a jQuery code that I have.

echo "<script>"          ."jQuery(document).ready(function() {"          ."var parts = jQuery('.casaPreco').text().split('|');"          ."jQuery('.casaPreco2').text(parts[4]);"          ."});"          ."</script>";

Basically the initial string is something like this: "3880562|1|1|925000|||0|0|0"

I need to grab the 4th number so I'm splitting the string on the "|" and use the array parts[4] but when I use the number_format it will grab the number "3880562"