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I have this function here that will print a string until it gets to the last character. The thing is I need it to do the opposite of that.

Instead of 'abc' printing 'abc, ab, c' I need it to print 'c, bc, abc'.

Thank you!

def reverse(string):  if len(string) == 0:    return string  else:    print(string)    return reverse(string[1:])

I have two strings. The first is normal string, the second I want to be a reversed string like first one, but in the console I didn't get the look of like first one listed by commas. How can I fix that ?

Normal string -

Revered string -

window.onload = function(){inputBox = document.getElementById("myText");btn = document.getElementById('sub');btn.addEventListener("click",function(event){event.preventDefault();    findPalindromes(inputBox.value);   });    str = inputBox.value;    function findPalindromes(str) {        var words = str.split(" ");            for (var i = 0; i < words.length - 1; i++) {                words[i] += " ";            }        console.log(words);        var newString = "";            for (var i = words.length - 1; i >= 0; i--) {                newString += words[i];            }        console.log(newString);     }} 

So I got stuck on a coding challenge that I almost knew the answer too. And I think I have to use the subString call in Swift 4 to get it 100%. I want to reverse every OTHER word in a string, but ignore or keep the punctuation in its original place( index ).

var sample = "lets start. And not worry about proper sentences."func reverseString(inputString: String) -> String {    let oldSentence = sample.components(separatedBy: " ")    var newSentence = ""    for index in 0...oldSentence.count - 1 {        let word = oldSentence[index]        if newSentence != "" {            newSentence += " "        }        if index % 2 == 1 {            let reverseWord = String(word.reversed())            newSentence += reverseWord        } else {            newSentence += word        }    }    return newSentence}reverseString(inputString: sample)

And this would be the expected output.

"lets trats. And ton worry tuoba proper secnetnes."

Notice the punctuation is not reversed.

My Task is to build a programm that takes a file as an argument and an optional argument that determines if the file will be outputted in reversed order. If the optional argument is "-r" then the content of the file will reverse when outputted.

#include <fstream>#include <iostream>#include <string>#include <algorithm>using std::cout;using std::string;using std::ios;using std::ifstream;using std::exception;int main(int argc,char *argv[]){    if (argc >= 2) {        string fileContent;        try        {            ifstream stream(argv[1]);            fileContent = string( (std::istreambuf_iterator<char>(stream) ),                       (std::istreambuf_iterator<char>()    ) );        }        catch (const exception&)        {            return 0;        }        if (argc == 3 && strcmp(argv[2],"-r") == 0){            std::reverse(fileContent.begin(),fileContent.end());        }        cout << fileContent;    }    return 0;}

This is my Python implementation of this problem. I ouputted the result in a new file and checked it with the solution we recived.(Checked if the hashes of both output files match). I noticted that Python's string reverse will not reverse '\r\n'.I do not think that there is an issues with the encoding of the file which should be utf-8.

import sysif len(sys.argv) >= 2:    with open(sys.argv[1],"r") as f:        string = str(f.read())        print(string[::-1] if len(sys.argv) == 3 and sys.argv[2] == "-r" else string,end="")

1. Is this only an issue for windows ?
2. How can I solve this problem ?

I'm trying to make a method that will take an array of strings and return an array with all the words in reverse order but my code is not working.

When I run it i get "[Ljava.lang.String;@74122d9c"

Test case: String[]words={"Monday","Tuesday","Wednesday"}; -->{"yadnoM","yadsueT","yadsendeW"};

public String[] reverseString(String[] words){    String[] t=new String[words.length];    for(int i=0;i<words.length;i++)    {        for(int j=words[i].length()-1;j>=0;j--)        {            t[i]+=words[i].substring(j,j+1);        }    }    return t;}