Hex en ligne en texte Decoder

I have a list like following:

\xeb\x1f\x5e\x31\xdb\x88\x5e\x07\x89\x76\x08\x89\x5e\x0c\x8d\x1e\x8d\x4e\x08\x8d\x56\x0c\x31\xc0\xb8\x0b\x00\x00\x00\xcd\x80\x31\xf6\xe8\xdc\xff\xff\xff\x2f\x62\x69\x6e\x2f\x73\x68\x41\x42\x42\x42\x42\x43\x43\x43\x43

I want to find \x00 and \xcd\x80 in the string and print it in highlight style. (for example with red color.). How can I do that?

I have a string that looks like this "7a" and I want to convert it to the hex number 7A. I have tried using pack and unpack but that is giving me the hex representation for each individual character.

I am trying to convert a string like "testing123" into hexadecimal form in java. I am currently using BlueJ.

And to convert it back, is it the same thing except backward?

I have a string like the following:\x31\xc0\xb8\x04\x00\x00\x00\x31\xdb\xb3\x01\x31\xd2\x52\x68\x72\x6c\x64\x0a\x68\x6f\x20\x57\x6f\x68\x48\x65\x6c\x6c\x89\xe1\xb2\x0c\xcd\x80\xb0\x01\xb3\x02\xcd\x80

I search it for null bytes with following code. The code works perfectly for searching one byte:

def ScanStringNullByte(_arg_string):        totalNullByte = 0        print("\033[101m\033[1mNull Bytes Detected:\033[0m\n")        for pos, check in enumerate(_arg_string):            if check == '\\x00':                print("\tNull byte at {} index".format(pos))                totalNullByte += 1        print("\n\t\033[95m\033[1mTotal null bytes in the shellcode: {}\033[0m\n".format(totalNullByte))

But I don't know how can I search the same string for two byte. for example I want to detect there are bytes like \xcd\x80 in the string or not. if there are, what location it is.

the are many ways to convert an integer to hex STRING, but is there a way to cast it to a hex literal as in?

string = zinteger = 122hex = 0X7A