הפוך מקוון מחרוזת

private def reverseHelper(word: String): String = {  var result = new StringBuilder(word)  if (word.head.isUpper) {    result.setCharAt(0, word.head.toLower)    result.setCharAt(word.length - 1, word.last.toUpper)  }  result.reverse.result()}

val formatString = str  .split("[.,!?: ]+")  .map(result => str.replaceFirst(result, reverseHelper(result)))  .foreach(println)

Example:
Input: What is a sentence?
Ouput: Tahw si a ecnetnes?

but i have Array[String]: Tahw is a sentence?, What si a sentence?, What is a sentence?, What is a ecnetnes?
How i can write this in right format?

I have homework assignment: to write a function that reverse a string, and then write a function that reverses words in a string, using the first function. So if the input is: "have a nice day", the output will be: "day nice a have".I cannot understand why my code isn't working - I keep getting segmentation fault.The first function (reverse) works just fine. The problem is with the second one.I really need your help...Thank you in advance.

#include <stdio.h>#include <string.h> #include <stdlib.h> void reverse(char *a){   int i, j, size;   char tmp;  size = strlen(a);  j=size-1;  for(i=0; i<size/2; i++)  {      tmp=a[i];      a[i]=a[j];      a[j]=tmp;      j--;  }}void reverseAll(char *a){   int size;   reverse(a);   size = strlen(a);   char *new = (char*)malloc(size+1);  char *token = strtok(a, " ");  reverse(token);  strcpy(new, token);  printf("%s ", new);  while(token != NULL)  {      reverse(token);      token = strtok(NULL, " ");      strcat(new, token);  }}int main(){   char a[15]= "have a nice day";    reverseAll(a);    printf("%s ", a);    return 0;}

I'm constrained to not use anything from <string.h>.

I want to reverse each word in the passed string.

This is what I have so far:

#include <stdio.h>char * reversepPrint( char *name ){    char *normal = name, *reverse = name;    while ( *reverse ) ++reverse;    if ( normal < reverse )    {        for ( ; normal < --reverse; ++normal  )        {            char c = *normal;            *normal = *reverse;            *reverse  = c;        }    }    return name;}int main( void ) {    char s[] = "Simon liebt Pizza!";    printf("%s", reversepPrint(s));    return 0;}

My code is reversing the whole string, but I want individual words to be reversed - so the result for this example would be "nomiS tbeil !azziP".

I want to reverse a string in C++ without using a loop or any other classes than std::string. Only the following methods should be used to reverse the string:x.at(); s.size()/s.length(); x.substr(pos,len);I think the usage of a recursion would be the solution to this problem, but I didn't figure it out how to do it right.

I tried this version, but it doesn't work.

string reverseWrapper(string str, int i, string stringToReturn) {if(i < 0) return stringToReturn;//cout << stringToReturn << '\n' << str.at(i) << '\n';stringToReturn.push_back(str.at(i));return reverseWrapper(str, int(str.size()) - 1, stringToReturn);}string reverseWithoutLoop(string str) {    string stringToReturn;    if(!(stringToReturn.length() == str.length())) {        return reverseWrapper(str, int(str.size()) - 1, stringToReturn);    }    return stringToReturn;}

Can you help me solving this problem?

I have a problem in string (array of characters) as a character take 3 places which make my code do unexpected result

check this code:

<?php$input1="t’n";for($i=0;$i<strlen($input1);$i++){    echo $input1[$i] .'<br/>';}echo '<br>'.'=================='.'<br>';$input2='test';for($i=0;$i<strlen($input2);$i++){    echo $input2[$i] .'<br/>';}echo '<br>'.'Strange ===> ';echo $input1[1].$input1[2].$input1[3];

see the photo:

As we noticed this character ’ take 3 places when deal with string as array of characters and the three must stay together to make the correct character.

I face this case when make a code that reverse a string I have input contain this character for example t’n => n’tAny suggestions?

Thanks in advance