ऑनलाइन हेक्स डिकोडर पाठ

I am struggling to convert a 'binary' strings like these into their corresponding MAC address

"\u0010\u00131n\\Ë" -> "10:13:31:6e:60:21""â¹å^<98>e" -> "e2:b9:e5:5e:98:65"

Hope someone can help me. I was trying something with:

printf 'â¹å^<98>e' | hexdump -C

but this does not give the expected outcome.

127.0.0.1:6379> setbit mykey 1 1(integer) 0127.0.0.1:6379> setbit mykey 23 1(integer) 0127.0.0.1:6379> setbit mykey 345 1(integer) 0127.0.0.1:6379> get mykey"@\x00\x01\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00@"127.0.0.1:6379>

I want to parse the above output string ( as a string of bits, like "100000000011...") to get the indexes of the set bits, how would I do it?

I have this string: Hello world !! and I want to print it using Python as 48:65:6c:6c:6f:20:77:6f:72:6c:64:20:21:21.

hex() works only for integers.

How can it be done?

I'm trying to turn a string representing a Hexidecimal number into an int in python without using the int constructor.

For example if I was given

    hexstring = "802"

How would I get that to be

    output = 2050

Without doing

    int("802",16)

How would I go about this?

When creating a String object in Swift you can use a String Format Specifier to convert an integer to hexadecimal notation.

print(String(format:"%x", 1234))// output: 4d2// expected output: 4d2

But when numbers become bigger, the output is not as expected.

print(String(format:"%x", 12345678901234))// output: 73ce2ff2// expected output: b3a73ce2ff2

It seems that the output of String(format:"%x", n) is truncated at 8 characters. I don't think in hexadecimal natively, this makes debugging hard. I have seen answers for other programming languages where it is explained that you need to brake-up the large integer into parts, but that seems wrong to me.

• What am I doing wrong here?
• What is the right way to convert decimal numbers to hexadecimal numbers in Swift?