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How can we convert from String to Hex in java

This code is part of AES encryption algorithm, I have this method that return the encrypted value as: String I need it to return the result as Hex instead .

public static String encrypt(String Data) throws NoSuchPaddingException, NoSuchAlgorithmException, InvalidKeyException, BadPaddingException, IllegalBlockSizeException {    Key key = generateKey();    Cipher c = Cipher.getInstance(ALGO);    c.init(Cipher.ENCRYPT_MODE, key);    byte[] encVal = c.doFinal(Data.getBytes());    String encryptedValue = new String( Base64.getEncoder().encode(encVal) ) ;    return encryptedValue;}

I am trying to convert a string like "testing123" into hexadecimal form in java. I am currently using BlueJ.

And to convert it back, is it the same thing except backward?

While importing data from a flat file, I noticed some embedded hex-values in the string (<0x00>, <0x01>).

I want to replace them with specific characters, but am unable to do so. Removing them won't work either.What it looks like in the exported flat file: https://i.imgur.com/7MQpoMH.pngAnother example: https://i.imgur.com/3ZUSGIr.png

This is what I've tried: (and mind, <0x01> represents a none-editable entity. It's not recognized here.)

import iowith io.open('1.txt', 'r+', encoding="utf-8") as p:    s=p.read()# included in case it bears any significance

import reimport binasciis = "Some string with hex: <0x01>"s = s.encode('latin1').decode('utf-8')# throws e.g.: >>> UnicodeDecodeError: 'utf-8' codec can't decode byte 0xfc in position 114: invalid start bytes = re.sub(r'<0x01>', r'.', s)s = re.sub(r'\\0x01', r'.', s)s = re.sub(r'\\\\0x01', r'.', s)s = s.replace('\0x01', '.')s = s.replace('<0x01>', '.')s = s.replace('0x01', '.')

or something along these lines in hopes to get a grasp of it while iterating through the whole string:

for x in s:    try:        base64.encodebytes(x)        base64.decodebytes(x)        s.strip(binascii.unhexlify(x))        s.decode('utf-8')        s.encode('latin1').decode('utf-8')    except:        pass

Nothing seems to get the job done.

I'd expect the characters to be replacable with the methods I've dug up, but they are not. What am I missing?NB: I have to preserve umlauts (äöüÄÖÜ)

-- edit:

Could I introduce the hex-values in the first place when exporting? If so, is there a way to avoid that?

with io.open('out.txt', 'w', encoding="utf-8") as temp:    temp.write(s)

I have this String c9e9a0f30c56fc4881f09b65070ecf6ad65f2a51bc910fd5 composed of hexadecimal characters only. Correct me if I'm wrong but a character on a String takes a byte for its representation right? But since a hexadecimal character fits in 4 bits I could fit two characters in a byte. Is there a simple way to do this in Java?

Thank you in advance! You guys rock!

Declaration of a method are following:

//some.hvoid TDES_Decryption(BYTE *Data, BYTE *Key, BYTE *InitalVector, int Length);

I am calling this method from the following code:

//some.cextern "C" __declspec(dllexport) bool _cdecl OnDecryption(LPCTSTR stringKSN, LPCTSTR BDK){    TDES_Decryption(m_Track1Buffer, m_cryptoKey, init_vector, len);    return m_Track1Buffer;}

Where as data type of m_Track1Buffer is BYTE m_Track1Buffer[1000];Now i want to make some changes in above method i.e. want to return the String in hex instead of Byte. How should i convert this m_Track1buffer to Hex string