I want to check and list the Md5sum for all the files in a zip folder. I am using windows OS. Can someone please suggest me a better way other than unzipping all the files and then checking the md5sum.
Packaging a folder on a SUSE Linux Enterprise Server 12 SP3 system using GNU tar 1.30 always gives different md5 checksums although the file contents do not change.
I run tar to package my folder that contains a simple text file:
tar cf package.tar folder
Nevertheless, although the content is exactly the same, the resulting tar always has a different md5 (or sha1) checksum:
$> rm -rf package.tar && tar cf package.tar folder && md5sum package.tare6383218596fffe118758b46e0edad1d package.tar$> rm -rf package.tar && tar cf package.tar folder && md5sum package.tar1c5aa972e5bfa2ec78e63a9b3116e027 package.tar
Because the linux file system seems to deliver files in a random order to tar, I tried using the
--sort option. But the resulting command doesn't change the checksum issue for me. Also tar's
--mtime option does not help here, since the creation dates are exactly the same.
I appreciate any help on this.
What's the best recommended method/approach to check on the "file originality" of large quantities of files in a directory?
Considering large quantities of files needed to transfer from one site to another site, there may possibility that the files are corrupted or unauthorized modification during transferring process.
Currently I am using Last Modified Date to check on the file to verify whether the file still remain the "original" copies.I found that through file checksum(MD5/sha1) maybe a better approach compared to check on Last Modified Date on files.
- Is it by using file MD5 is best approach/method to check/verify the files? Or there is any better alternate method/approach?
- How about the performance side? Cpu intensive? By generating MD5/sha1 are efficient and quick enough to process large quantities of files? Will size of file affect the MD5 generating time taken?
I'm trying to convert a file into .docx using aspose
However, even though the file generated in Microsoft Word looks identical to the MD5 of the generated file, it is different each time I run the same program.Is there a way to ensure that file integrity using aspose?
Here is a snippet of the code:
System.out.println(DigestUtils.md5Hex(bytes));ByteArrayInputStream bis = new ByteArrayInputStream(bytes);Document doc = new Document(bis);doc.save("newFile.docx");bis.close();bytes= FileUtils.readFileToByteArray(new File("newFile.docx");System.out.println(DigestUtils.md5Hex(bytes)); //<-- generates a MD5 that is different each time I run the program...why??
My question is, is there a way to ensure we get identical MD5 hash after each run?
Linux distros such as CentOS (v6.3 i.e.) are using a specific boot manager such as "GRUB", which contains a .conf file where you can edit your user information such as your password etc.
the password must be encrypted using MD5 (i.e. : Password --md5 kw485/fgf$&e), and that is a little bit confusing.
Assuming that the MD5 is a one way encrypting method and that encrypting the same string will always give a newly generated string.
How can the system compare the two passwords since they'll never match ?
here is an example :
grub> md5cryptmd5cryptPassword: hellohelloEncrypted: $1$95Uz30$X/u7PX4F5GtEOsMguDDq10grub> md5cryptmd5cryptPassword: hellohelloEncrypted: $1$H8Uz30$LwAkSMZBYC07zJbx3lIVa1
as you can see we have inserted the same string and got two different results, assuming that's how a login scenario should happen such as :
$ login userpassword : hello
$1$H8Uz30$LwAkSMZBYC07zJbx3lIVa1hashedpassword in grub.conf is
$1$95Uz30$X/u7PX4F5GtEOsMguDDq10that's afailed login attempt.