I am struggling to convert a 'binary' strings like these into their corresponding MAC address
"\u0010\u00131n\\Ë" -> "10:13:31:6e:60:21""â¹å^<98>e" -> "e2:b9:e5:5e:98:65"
Hope someone can help me. I was trying something with:
printf 'â¹å^<98>e' | hexdump -C
but this does not give the expected outcome.
127.0.0.1:6379> setbit mykey 1 1(integer) 0127.0.0.1:6379> setbit mykey 23 1(integer) 0127.0.0.1:6379> setbit mykey 345 1(integer) 0127.0.0.1:6379> get mykey"@\x00\x01\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00@"127.0.0.1:6379>
I want to parse the above output string ( as a string of bits, like "100000000011...") to get the indexes of the set bits, how would I do it?
I have this string:
Hello world !! and I want to print it using Python as
hex() works only for integers.
How can it be done?
I'm trying to turn a string representing a Hexidecimal number into an int in python without using the int constructor.
For example if I was given
hexstring = "802"
How would I get that to be
output = 2050
How would I go about this?
When creating a String object in Swift you can use a String Format Specifier to convert an integer to hexadecimal notation.
print(String(format:"%x", 1234))// output: 4d2// expected output: 4d2
But when numbers become bigger, the output is not as expected.
print(String(format:"%x", 12345678901234))// output: 73ce2ff2// expected output: b3a73ce2ff2
It seems that the output of
String(format:"%x", n) is truncated at 8 characters. I don't think in hexadecimal natively, this makes debugging hard. I have seen answers for other programming languages where it is explained that you need to brake-up the large integer into parts, but that seems wrong to me.