Encoder Url ออนไลน์

I've got a string like "foo%20bar" and I want "foo bar" out of it.

I know there's got to be a built-in function to decode a URL-encoded string (query string) in Emacs Lisp, but for the life of me I can't find it today, either in my lisp/ folder or with google.

Anybody remember what it's called?

My Java standalone application gets a URL (which points to a file) from the user and I need to hit it and download it. The problem I am facing is that I am not able to encode the HTTP URL address properly...

Example:

URL:  http://search.barnesandnoble.com/booksearch/first book.pdfjava.net.URLEncoder.encode(url.toString(), "ISO-8859-1");

returns me:

http%3A%2F%2Fsearch.barnesandnoble.com%2Fbooksearch%2Ffirst+book.pdf

But, what I want is

http://search.barnesandnoble.com/booksearch/first%20book.pdf

(space replaced by %20)

I guess URLEncoder is not designed to encode HTTP URLs... The JavaDoc says "Utility class for HTML form encoding"... Is there any other way to do this?

If I encode a string like this:

var escapedString = originalString.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)

it doesn't escape the slashes /.

I've searched and found this Objective C code:

NSString *encodedString = (NSString *)CFURLCreateStringByAddingPercentEscapes(                        NULL,                        (CFStringRef)unencodedString,                        NULL,                        (CFStringRef)@"!*'();:@&=+$,/?%#[]",                        kCFStringEncodingUTF8 );

Is there an easier way to encode an URL and if not, how do I write this in Swift?

I've been searching for this problem but non was identical to my case.

I have the following controller:

 public HttpResponseMessage GetMyService(int aType, [FromUri] string streamURL)

streamURL is a parameter that gets a full URL sent by the client.

The client calls the service like that:http://www.myservice.com/.../GetMyService/?aType=1&streamURL=http://www.client.com/?p1=100&p2=200

The problem is that at then end, I get the [FromUri] string streamURL parameter as http://www.client.com/?p1=100 without the &p2=200

This is known and reasonable, but I cannot place any encoding/decoding functionality as the URL is cut at the very beginning.

Any help would be appreciated..

THX

I am working with Python 3.5.1 / Window 8.1

>>pip install -e git://github.com/kvesteri/flask-storage.git#egg=Flask-Storage

This is the outcome:

Obtaining Flask-Storage from git+git://github.com/kvesteri/flask-storage.git#egg=Flask-Storage  Updating c:\users\rodolfo\desktop\dumppython\flask\venv\src\flask-storage cloneRequirement already satisfied: Flask>=0.7 in c:\users\rodolfo\desktop\dumppython\flask\venv\lib\site-packages (from Flask-Storage)Requirement already satisfied: boto>=2.5.2 in c:\users\rodolfo\desktop\dumppython\flask\venv\lib\site-packages (from Flask-Storage)Collecting python-cloudfiles>=1.7.10 (from Flask-Storage)  Using cached python-cloudfiles-1.7.11.tar.gz    Complete output from command python setup.py egg_info:    Traceback (most recent call last):      File "<string>", line 1, in <module>      File "C:\Users\Rodolfo\AppData\Local\Temp\pip-build-t2cefnr2\python-cloudfiles\setup.py", line 6, in <module>        from cloudfiles.consts import __version__      File "C:\Users\Rodolfo\AppData\Local\Temp\pip-build-t2cefnr2\python-cloudfiles\cloudfiles\__init__.py", line 82, in <module>        from cloudfiles.connection     import Connection, ConnectionPool      File "C:\Users\Rodolfo\AppData\Local\Temp\pip-build-t2cefnr2\python-cloudfiles\cloudfiles\connection.py", line 13, in <module>        from    urllib    import urlencode    ImportError: cannot import name 'urlencode'