Online Baliktarin ang String

I am doing an assignment where I have to implement a function reverse() that reverses the string between indexes i and j inclusively. reverse(str, 0, 4) will reverses the string between indexes of 0 and 4 from apple to elppa.All words can be reversed by finding start and end positions of each word and reversing the word.

void reverse(char *str, int i, int j). for example

userinput:

apple orange banana

will output:

elppa egnaro ananab

but my code prints nothing. I know thereare a lot of bugs but I am stuck and don't know how to go from here. My code is:

#include <stdio.h>#include <string.h>void reverse(char *str, int i, int j);int i, j, k, len, ind, temp;char str[100];int main(){    printf("Enter a string: \n");    gets(str);    len = strlen(str);    reverse(str, i, j);    return 0;}void reverse(char *str, int i, int j){    for (i = 0; i < len; i++)//    {        ind = i;            //index of the end of each word        if (str[i] == ' ' || str[i] == '\n')//ends at index of whites space        {            ind = i - 1;//index of empty space -1            i= 0;//i is reset to 0            if (i <= ind)//0<last index of word            {                //reverse                temp = str[i];                str[i] = str[ind];                str[ind] = temp;            }        }      }   printf("%s\n",str[i]);}

I want to know how Python3 implemented some built-in functions as follows:

1. How Python reverses a string:
   • I know that in Python we can easily reverse a string by s=s[::-1], but how this happened? Does Python user a for-loop inversely and copy every character in the string into a new string and return?
2. How python compares two strings:
   • In Python, we can easily check if two string is equal by s1==s2. However, how Python implements it? Is it a for-loop and compare one by one?

I often get into such confusions and don't know where can I find the answers. Can anybody tell me where can I find the source codes that can explain such questions related to Python built-in functions to me? Thanks in advance!

I am unable to find problem in this code. I want to reverse the string without reversing special characters. So, if the string is 'ab#$cd!' ,the output would be 'dc#$ba!' the output I am getting is 'ab#$cd!' (the same as input).

Kindly find the problem in the code.

function isAlphabet(x) {  if ((x >= 'A' && x <= 'Z') || (x >= 'a' && x <= 'z')) {    return true  } else {    return false  }}function reverse() {  var string1 = [];  string1 = 'ab#$cd!'  var n = string1.length;  var r = n - 1;  var i = 0;  while (i < r) {    if (!isAlphabet(string1[i])) {      i++;    } else if (!isAlphabet(string1[r])) {      r--;    } else {      var temp;      temp = string1[i];      string1[i] = string1[r];      string1[r] = temp;      i++;      r--;    }  }  return string1;}console.log(reverse());

I am learning how to reverse strings (i.e., write backwards) from first principles in C++. I devised the following code that is meant to take in a string from the user, reverse it, and print it out. However, it fails to compile—Visual Studio gives me an error "string subset out of range". What is wrong?

using namespace std;int main(){    string example;    getline(cin, example);    int i = 0;    while (example[i] != '\0')     {        i++;    }    int n=0;    string reverse;    while (n < i)    {        reverse[n] = example[i - n - 1];        n++;    }    cout << reverse << endl;    return 0;}

I am targeting C++17.

I have analysed the global header of a PCAP file and found out that the magic number is: d4 c3 b2 a1

This means that it uses a little endian and all the bytes that come after it need to processed in reverse order. The other sections of the global header are as follows:

major version =  02 00minor version =  04 00time zone =  00 00 00 00timestamp =  00 00 00 00snaplen =  ff ff 00 00linktype =  01 00 00 00

However given that little endian is in use, it should be:

major version =  00 02minor version =  00 04time zone =  00 00 00 00timestamp =  00 00 00 00snaplen =  00 00 ff fflinktype =  00 00 00 01

So I need a way to reverse the string but still keep the pairs of characters separated by the spaces in the same order.

So the code [::-1] will not work because it transforms 02 00 into 00 20, whereas it needs to be 00 02

How would I go about doing this?