在線六角到文本解碼器

I get below result from a web service:

 "\\x52\\x50\\x1F\\x1F\\x44\\x46\\x57\\x47"

I need to get the strings in unicode characters, which i think would be:

"\u0052\u0050\u001F\u001F\u0044\u0046\u0057\u0047"

i.e. "RPDFWG"

I cannot use replace("\\x", "\u00"); because it says "\u00" is not a valid unicode

I have ABC123EFFF.

I want to have 001010101111000001001000111110111111111111 (i.e. binary repr. with, say, 42 digits and leading zeroes).

How?

I have the following code...

int Val=-32768;String Hex=Integer.toHexString(Val);

This equates to ffff8000

int FirstAttempt=Integer.parseInt(Hex,16); // Error "Invalid Int"int SecondAttempt=Integer.decode("0x"+Hex);  // Error "Invalid Int"

So, initially, it converts the value -32768 into a hex string ffff8000, but then it can't convert the hex string back into an Integer.

In .Net it works as I'd expect, and returns -32768.

I know that I could write my own little method to convert this myself, but I'm just wondering if I'm missing something, or if this is genuinely a bug?

I'm trying to decode hex string to binary values. I found this below command on internet to get it done,

string_bin = string_1.decode('hex')

but I got error saying

'str' object has no attrubute 'decode'

I'm using python v3.4.1

I want to take an integer (that will be <= 255), to a hex string representation

e.g.: I want to pass in 65 and get out '\x41', or 255 and get '\xff'.

I've tried doing this with the struct.pack('c',65), but that chokes on anything above 9 since it wants to take in a single character string.