I get below result from a web service:
"\\x52\\x50\\x1F\\x1F\\x44\\x46\\x57\\x47"
I need to get the strings in unicode characters, which i think would be:
"\u0052\u0050\u001F\u001F\u0044\u0046\u0057\u0047"
i.e. "RPDFWG"
I cannot use replace("\\x", "\u00");
because it says "\u00" is not a valid unicode
I have ABC123EFFF.
I want to have 001010101111000001001000111110111111111111 (i.e. binary repr. with, say, 42 digits and leading zeroes).
How?
I have the following code...
int Val=-32768;String Hex=Integer.toHexString(Val);
This equates to ffff8000
int FirstAttempt=Integer.parseInt(Hex,16); // Error "Invalid Int"int SecondAttempt=Integer.decode("0x"+Hex); // Error "Invalid Int"
So, initially, it converts the value -32768 into a hex string ffff8000, but then it can't convert the hex string back into an Integer.
In .Net
it works as I'd expect, and returns -32768
.
I know that I could write my own little method to convert this myself, but I'm just wondering if I'm missing something, or if this is genuinely a bug?
I'm trying to decode hex string to binary values. I found this below command on internet to get it done,
string_bin = string_1.decode('hex')
but I got error saying
'str' object has no attrubute 'decode'
I'm using python v3.4.1
I want to take an integer (that will be <= 255), to a hex string representation
e.g.: I want to pass in 65
and get out '\x41'
, or 255
and get '\xff'
.
I've tried doing this with the struct.pack('c',
65)
, but that chokes on anything above 9
since it wants to take in a single character string.
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